(1/25)^(2x+3)=125^(9x+8)

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Solution for (1/25)^(2x+3)=125^(9x+8) equation: 



(1/25)^(2x+3)=125^(9x+8)

We move all terms to the left:

(1/25)^(2x+3)-(125^(9x+8))=0



Domain of the equation: 25)^(2x+3)!=0

x∈R



We add all the numbers together, and all the variables

(+1/25)^(2x+3)-(125^(9x+8))=0

We multiply all the terms by the denominator


(+1-((125^(9x+8)))*25)^(2x+3)=0



We calculate terms in parentheses: +(+1-((125^(9x+8)))*25)^(2x+3), so:

+1-((125^(9x+8)))*25)^(2x+3

determiningTheFunctionDomain
-((125^(9x+8)))*25)^(2x+1+3

We add all the numbers together, and all the variables

-((125^(9x+8)))*25)^(2x+4

Back to the equation:

+(-((125^(9x+8)))*25)^(2x+4)





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((125^(9x+8)))*25)^(2x+4), so:

-((125^(9x+8)))*25)^(2x+4





We calculate terms in parentheses: +(-((1

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